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Proof step 3 from proof referenced-adrs-one (previous step)

⊦ referenced-adrs(adr + [], ri) = (adr ∈ ri ⊃ adr + [];[])

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ adr + ax = adr ' + ax
Proof step 5:
⊦ referenced-adrs(adr ' + [], ri) = (adr ∈ ri ⊃ adr ' + [];[])

Rule argument

spec: list, inst: address-list-set name: c seq: ⊦ adr + ax = adr ' + ax subst: [ax, adr] → [[], adr] flags: <all paths>

Additional information

Used terms: [], adr