[Imprint][Data Privacy Statement][E-Mail]

View long theorem info. View the proof. Back to main index. View the specification. View theorem base summary, View theorem base listing, the used properties by spec, the dependency list, the symbol table,

Proof step 11 from proof refsize-cons-in-ri-0 (previous step)

0 = (range ri | m).size, gstore[m] = groupblock(gndx, lax, 0), @(m, m0, m1) ∈ ri, m ∈ gstore, ri.lebs ⊆ dom gstore ⊦ m1 = 0

User applied rule cut formula

And obtained the following new goals

Proof step 12:
0 = (range ri | m).size, gstore[m] = groupblock(gndx, lax, 0), m ∈ gstore, @(m, m0, m1) ∈ ri, @(m, m0, m1) ∈ range ri, ri.lebs ⊆ dom gstore ⊦ m1 = 0

Rule argument

fma: @(m, m0, m1) ∈ range ri

Additional information

Used simplifier rules: ⊦ adr ∈ range ri ↔ adr ∈ ri; (s) Used formulas: @(m, m0, m1) ∈ range ri