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Proof step 3 from proof refsize-cons-in-ri-0 (previous step)

gstore[adr.lnum].ref-size = 0, refsize-cons(gstore, range ri), adr ∈ ri, adr.lnum ∈ gstore, ri.lebs ⊆ dom gstore ⊦ adr.size = 0

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 4:
gstore[m].ref-size = 0, adr = @(m, m0, m1), refsize-cons(gstore, range ri), m ∈ gstore, adr ∈ ri, ri.lebs ⊆ dom gstore ⊦ m1 = 0

Rule argument

spec: address-data name: elim seq: ⊦ (m = adr.lnum ∧ m0 = adr.pos) ∧ m1 = adr.size ↔ adr = @(m, m0, m1) subst: [adr, m, m0, m1] → [adr, m, m0, m1]

Additional information

Used simplifier rules: ⊦ (m = adr.lnum ∧ m0 = adr.pos) ∧ m1 = adr.size ↔ adr = @(m, m0, m1); (elim) Used terms: adr, m, m0, m1