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Proof step 46 from proof initialization (previous step)

err = err1, ⌊err1⌋ ⊦ ⟨ri := ?, fs := ?, fi := ?, fo := ?, ro := ?, log := ?, jvalid := ?⟩ (ri1 = ri ∧ fi0 = fi ∧ ro1 = ro ∧ fo1 = fo ∧ fs1 = fs ∧ log1 = log ∧ (jvalid1 ↔ jvalid) ∧ err1 = err)

Proof step 46 from proof initialization (previous step)

Heuristic symbolic execution applied rule assign right

And closed the goal!

Rule argument

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