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Proof step 26 from proof refine-get (previous step)

jvalid ↔ jvalid2, gstore2[@(m, m0, m1)] = mkgnode(nd1, m2, boolvar, boolvar0), adr = @(m, m0, m1), fi = fi1, fo = p_os.keys, fs = nodes(gstore2 ↓, jro0), log = abs-log(nx, gstore2 ↓), nd = nd0, remove-refsize0(gstore1) = gstore1, ro = jro1.keys, elems nx ∩ jro0 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ jro0, p_os.keys.inodes?, jro1.keys.inodes?, fi1.inos < pmaxino, ri.inos < jmaxino, p_os < pmaxino, jro1 < jmaxino, inv(gstore1), inv(gstore2 \ jro0), log-cons(abs-log(nx, gstore2 ↓), nodes(gstore2 ↓, jro0)), refsize-cons(gstore1, range fi1), refsize-cons(gstore2, range ri), ri-inj(fi1), ri-inj(ri), @(m, m0, m1) ∈ nodes(gstore2 ↓, jro0), @(m, m0, m1) ∈ gstore2, pmaxino ≤ jmaxino, fi1.lebs ⊆ dom gstore1, ri.lebs ⊆ dom gstore2, jvalid1 ∧ nx ≠ [] → valid-journal-head(nx, gstore2, jro0), jvalid2 → jvalid0 ⊦ ⟨fail#(; ; err)⟩ ((jvalid2 → jvalid0) ∧ nd1 = nd ∧ ESUCCESS = err), ⟨nd := fs[adr], err := ESUCCESS⟩ ((jvalid2 → jvalid0) ∧ nd1 = nd ∧ ESUCCESS = err), jmaxino = 0, pmaxino = 0, dups(nx), m ∈ jro0

Heuristic symbolic execution applied rule assign right

And closed the goal!

Rule argument

pos: right 2

Additional information

Used simplifier rules: ⊦ adr ∈ nodes(gstore, ginval) → nodes(gstore, ginval)[adr] = gstore[adr].nd; (s)%⊦ adr ∈ nodes(gstore ↓, ginval) ∧ gstore[adr] = gnd → gstore ↓[adr] = gstore[adr]; (s)% ⊦ mkgnode(nd, m, boolvar, boolvar0).nd = nd; (s)