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Proof step 49 from proof refine-lookup (previous step)

jvalid ↔ key ∈ ri, gstore2[@(m, m0, m1)] = mkgnode(nd1, m2, boolvar, boolvar0), ri[key] = @(m, m0, m1), err = ESUCCESS, remove-refsize0(gstore1) = gstore1, elems nx ∩ jro0 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ jro0, p_os.keys.inodes?, jro1.keys.inodes?, fi1.inos < pmaxino, ri.inos < jmaxino, p_os < pmaxino, jro1 < jmaxino, inv(gstore1), inv(gstore2 \ jro0), log-cons(abs-log(nx, gstore2 ↓), nodes(gstore2 ↓, jro0)), refsize-cons(gstore1, range fi1), refsize-cons(gstore2, range ri), ri-cons(ri, nodes(gstore2 ↓, jro0)), ri-inj(fi1), ri-inj(ri), @(m, m0, m1) ∈ gstore2, key ∈ ri, m ∈ gstore2, pmaxino ≤ jmaxino, fi1.lebs ⊆ dom gstore1, ri.lebs ⊆ dom gstore2, jvalid1 ∧ nx ≠ [] → valid-journal-head(nx, gstore2, jro0), jvalid4 → jvalid2 ⊦ ⟨nd := nodes(gstore2 ↓, jro0)[ri[key]]⟩ ((jvalid4 → jvalid2) ∧ jvalid ∧ nd1 = nd ∧ ESUCCESS = err), jmaxino = 0, pmaxino = 0, dups(nx), m ∈ jro0

Heuristic symbolic execution applied rule assign right

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ key ∈ ri ∧ ri-cons(ri, fs) → ri[key] ∈ fs; (ss)%⊦ adr ∈ nodes(gstore, ginval) → nodes(gstore, ginval)[adr] = gstore[adr].nd; (s)%⊦ adr ∈ nodes(gstore ↓, ginval) ∧ gstore[adr] = gnd → gstore ↓[adr] = gstore[adr]; (s)% ⊦ mkgnode(nd, m, boolvar, boolvar0).nd = nd; (s)