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Proof step 35 from proof inv-add-gnds (previous step)

fi = fi1, fi0 = fi2, ginval = ginval1, ginval0 = ginval2, remove-refsize0(gstore0) = gstore0, elems nx ∩ ginval2 = ∅, dom gstore0 ∪ elems nx = dom gstore ∪ ginval2, inv(gstore[nx.last]), inv(gstore0), inv(gstore \ ginval2), ri-inj(fi1), ri-inj(fi2), nx.last ∈ gstore ⊦ nx = [], dups(nx), ∀ lax, err0. ⌊err0⌋ ∨ err0 = ESUCCESS → nx.last ∈ gstore ∧ nx ≠ []

Proof step 35 from proof inv-add-gnds (previous step)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

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