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Proof step 5 from proof inv-allocate-gnd (previous step)

syn ↔ true, fi = fi1, fi0 = fi2, remove-refsize0(gstore0) = gstore0, elems nx ∩ ginval = ∅, dom gstore0 ∪ elems nx = dom gstore ∪ ginval, inv(gstore \ ginval), inv(gstore0), ri-inj(fi2), ri-inj(fi1) ⊦ ⟪fail_or_success#(; ; err); if err = ESUCCESS then choose n with ¬ n ∈ gstore in gstore[n] := groupblock([], [], 0), nx := nx + n, ginval := ginval -- n⟫ (inv(gstore \ ginval) ∧ elems nx ∩ ginval = ∅ ∧ ¬ dups(nx) ∧ dom gstore0 ∪ elems nx = dom gstore ∪ ginval), dups(nx)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
remove-refsize0(gstore0) = gstore0, elems nx ∩ ginval = ∅, dom gstore0 ∪ elems nx = dom gstore ∪ ginval, inv(gstore0), inv(gstore \ ginval), ri-inj(fi1), ri-inj(fi2), ¬ dups(nx) ⊦ ⟪fail_or_success#(; ; err); if err = ESUCCESS then choose n with ¬ n ∈ gstore in gstore[n] := groupblock([], [], 0), nx := nx + n, ginval := ginval -- n⟫ (inv(gstore \ ginval) ∧ elems nx ∩ ginval = ∅ ∧ ¬ dups(nx) ∧ dom gstore0 ∪ elems nx = dom gstore ∪ ginval)

Proof step 5 from proof inv-allocate-gnd (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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