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Proof step 3 from proof inv-get-block-free-size (previous step)

remove-refsize0(gstore0) = gstore0, elems nx ∩ ginval = ∅, dom gstore0 ∪ elems nx = dom gstore ∪ ginval, inv(gstore \ ginval), inv(gstore0), ri-inj(fi), ri-inj(fi0), ¬ dups(nx) ⊦ ⟪index_get_block_free_size#(fi, fi0, ginval, gstore, gstore0, nx, maxino, ginval0, syn; ; n)⟫ true

Heuristic unfold applied rule call right

And obtained the following new goals

Proof step 4:
fi = fi1, fi0 = fi2, ginval = ginval1, ginval0 = ginval2, gstore = gstore1, gstore0 = gstore2, remove-refsize0(gstore1) = gstore1, elems nx ∩ ginval2 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ ginval2, inv(gstore1), inv(gstore2 \ ginval2), ri-inj(fi1), ri-inj(fi2) ⊦ ⟪choose n0 with n0 ≤ LEB_SIZE in n := n0⟫ true, dups(nx)

Rule argument

pos: right 1

Additional information

Used simplifier rules: get-block-free-size: ⊦ ;