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Proof step 5 from proof inv-get-block-free-size (previous step)

fi = fi1, fi0 = fi2, ginval = ginval1, ginval0 = ginval2, gstore = gstore1, gstore0 = gstore2, remove-refsize0(gstore1) = gstore1, elems nx ∩ ginval2 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ ginval2, inv(gstore2 \ ginval2), inv(gstore1), ri-inj(fi2), ri-inj(fi1), n0 ≤ LEB_SIZE ⊦ ⟪n := n0⟫ true, dups(nx)

Proof step 5 from proof inv-get-block-free-size (previous step)

Heuristic symbolic execution applied rule assign right

And closed the goal!

Rule argument

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