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Proof step 6 from proof inv-get-block-free-size (previous step)

fi = fi1, fi0 = fi2, ginval = ginval1, ginval0 = ginval2, gstore = gstore1, gstore0 = gstore2, remove-refsize0(gstore1) = gstore1, elems nx ∩ ginval2 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ ginval2, inv(gstore2 \ ginval2), inv(gstore1), ri-inj(fi2), ri-inj(fi1) ⊦ dups(nx), ∃ n0. n0 ≤ LEB_SIZE

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
remove-refsize0(gstore1) = gstore1, elems nx ∩ ginval2 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ ginval2, inv(gstore1), inv(gstore2 \ ginval2), ri-inj(fi1), ri-inj(fi2) ⊦ dups(nx), ∃ n0. n0 ≤ LEB_SIZE

Proof step 6 from proof inv-get-block-free-size (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information