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Proof step 4 from proof inv-get-gc-block (previous step)

fi = fi1, fi0 = fi2, ginval = ginval1, ginval0 = ginval2, gstore = gstore1, gstore0 = gstore2, n0 = n, remove-refsize0(gstore1) = gstore1, elems nx ∩ ginval2 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ ginval2, inv(gstore1), inv(gstore2 \ ginval2), ri-inj(fi1), ri-inj(fi2) ⊦ ⟪err := ENOSPC or choose n with n ∈ dom gstore0 ∧ ¬ n ∈ nx in {n0 := n; err := ESUCCESS} ifnone err := ENOSPC⟫ true, dups(nx)

Heuristic conditional right split applied rule or split right

And obtained the following new goals

Proof step 5:
fi = fi1, fi0 = fi2, ginval = ginval1, ginval0 = ginval2, gstore = gstore1, gstore0 = gstore2, n0 = n, remove-refsize0(gstore1) = gstore1, elems nx ∩ ginval2 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ ginval2, inv(gstore2 \ ginval2), inv(gstore1), ri-inj(fi2), ri-inj(fi1) ⊦ ⟪err := ENOSPC⟫ true, dups(nx)
Proof step 6:
fi = fi1, fi0 = fi2, ginval = ginval1, ginval0 = ginval2, gstore = gstore1, gstore0 = gstore2, n0 = n, remove-refsize0(gstore1) = gstore1, elems nx ∩ ginval2 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ ginval2, inv(gstore2 \ ginval2), inv(gstore1), ri-inj(fi2), ri-inj(fi1) ⊦ ⟪choose n with n ∈ dom gstore0 ∧ ¬ n ∈ nx in {n0 := n; err := ESUCCESS} ifnone err := ENOSPC⟫ true, dups(nx)

Proof step 4 from proof inv-get-gc-block (previous step)

Heuristic conditional right split applied rule or split right

And obtained the following new goals

Rule argument

Additional information