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Proof step 9 from proof inv-read-gnd (previous step)

remove-refsize0(gstore1) = gstore1, elems nx ∩ ginval2 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ ginval2, inv(gstore2 \ ginval2), inv(gstore1), ri-inj(fi2), ri-inj(fi1), @(m, m0, m1) ∈ gstore2 ⊦ ⟪choose err0 with ⌊err0⌋ ∨ err0 = ESUCCESS in err := err0; if err = ESUCCESS then gnd := gstore2[@(m, m0, m1)] else gnd := ?⟫ true, dups(nx), m ∈ ginval2

Heuristic symbolic execution applied rule choose right

And obtained the following new goals

Proof step 10:
remove-refsize0(gstore1) = gstore1, elems nx ∩ ginval2 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ ginval2, inv(gstore1), inv(gstore2 \ ginval2), ri-inj(fi1), ri-inj(fi2), @(m, m0, m1) ∈ gstore2, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪err := err0; if err = ESUCCESS then gnd := gstore2[@(m, m0, m1)] else gnd := ?⟫ true, dups(nx), m ∈ ginval2
Proof step 14:
remove-refsize0(gstore1) = gstore1, elems nx ∩ ginval2 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ ginval2, inv(gstore1), inv(gstore2 \ ginval2), ri-inj(fi1), ri-inj(fi2), @(m, m0, m1) ∈ gstore2 ⊦ dups(nx), m ∈ ginval2, ∃ err0. ⌊err0⌋ ∨ err0 = ESUCCESS

Proof step 9 from proof inv-read-gnd (previous step)

Heuristic symbolic execution applied rule choose right

And obtained the following new goals

Rule argument

Additional information