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Proof step 4 from proof inv-recovery (previous step)

ginval = ginval4, ginval0 = ginval2, ginval1 = ginval3, gstore = gstore1, gstore0 = gstore3, gstore3 = crash(gstore2, gstore1, ginval4, nx), maxino0 = maxino1, nx0 = nx1, remove-refsize0(gstore1) = gstore1, elems nx ∩ ginval4 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ ginval4, inv(gstore1), inv(gstore2 \ ginval4), ri-inj(fi0), ri-inj(fi1) ⊦ ⟪fail_or_success#(; ; err); if err = ESUCCESS then maxino0 := maxino, syn := true, nx0 := nx, ginval1 := ginval0, fi := fi0 else ginval := ?, syn := ?, gstore0 := ?, gstore := ?, nx := ?, maxino := ?, ginval0 := ?, maxino0 := ?, nx0 := ?, ginval1 := ?, fi := ?, fi0 := ?⟫ ( err = ESUCCESS → syn ∧ inv(gstore0 \ ginval) ∧ inv(gstore) ∧ elems nx ∩ ginval = ∅ ∧ ¬ dups(nx) ∧ dom gstore ∪ elems nx = dom gstore0 ∪ ginval ∧ remove-refsize0(gstore) = gstore ∧ ri-inj(fi) ∧ ri-inj(fi0)), dups(nx)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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