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Proof step 15 from proof lookup-range-rem-union (previous step)

∃ key. key ∈ ri ∧ ri[key] = adr ⊦ ∃ key. key ∈ ks ∧ key ∈ ri ∧ adr = ri[key], ∃ key. key ∈ ri \ ks ∧ (ri \ ks)[key] = adr

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information