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Proof step 17 from proof lookup-range-rem-union (
previous step
)
key ∈ ri ⊦ ∃ key0. key0 ∈ ri \ ks ∧ (ri \ ks)[key0] = ri[key], key ∈ ks ∧ key ∈ ri ∧ ri[key] = ri[key]
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 18
:
key ∈ ri ⊦ key ∈ ks, ∃ key0. key0 ∈ ri \ ks ∧ (ri \ ks)[key0] = ri[key]
Rule argument
Additional information