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Proof step 10 from proof lookup-rem-inj-range-inter-empty (
previous step
)
⊦ ri-inj(ri) ↔ (∀ key0, key1. key0 ∈ ri ∧ key1 ∈ ri ∧ ri[key0] = ri[key1] → key0 = key1)
A spec-lemma