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Proof step 1 from proof inv-crash (conclusion)

pebs = pebs0, mtd-cons(pebs0) ⊦ ⟪skip⟫ mtd-cons(pebs)

Heuristic symbolic execution applied rule skip right

And closed the goal!

Rule argument

Additional information

Used simplifier rules: reduce-mtd-cons: ⊦ mtd-cons(pebs0) → ( mtd-cons(pebs1) ↔ (∀ n. n < # pebs1 ∧ (n < # pebs0 → mtd-valid-peb(pebs0[n])) → mtd-valid-peb(pebs1[n])));%⊦ mtd-valid-peb(peb) ↔ # peb.data = PEB_SIZE ∧ ( ¬ peb.bad → peb.fill ≤ PEB_SIZE ∧ is-aligned(peb.fill, EB_PAGE_SIZE) ∧ range= (peb.data, peb.fill, emptypeb, peb.fill, PEB_SIZE - peb.fill)); (s)