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Proof step 12 from proof inv-erase (previous step)

pebs[m] = mkpeb(buf, m0, false), err0 = ESUCCESS, m < # pebs, mtd-cons(pebs), ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪pebs[m] := mkpeb(emptypeb, 0, pebs[m].bad)⟫ mtd-cons(pebs)

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Proof step 13:
pebs[m] = mkpeb(buf, m0, false), err0 = ESUCCESS, m < # pebs, mtd-cons(pebs), ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ mtd-cons(pebs[m, mkpeb(emptypeb, 0, pebs[m].bad)])

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ ⌊ESUCCESS⌋ ; (s)