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Proof step 3 from proof inv-init (previous step)

⊦ ⟪choose err0 with ⌊err0⌋ ∨ err0 = ESUCCESS in err := err0; choose pebs with err = ESUCCESS → mtd-cons(pebs) in pebs0 := pebs⟫ ((err = ESUCCESS → mtd-cons(pebs0)) ∧ (err = ESUCCESS ∨ ⌊err⌋ ))

Heuristic symbolic execution applied rule choose right

And obtained the following new goals

Proof step 4:
⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪err := err0; choose pebs with err = ESUCCESS → mtd-cons(pebs) in pebs0 := pebs⟫ ((err = ESUCCESS → mtd-cons(pebs0)) ∧ (err = ESUCCESS ∨ ⌊err⌋ ))
Proof step 11:
⊦ ∃ err0. ⌊err0⌋ ∨ err0 = ESUCCESS

Proof step 3 from proof inv-init (previous step)

Heuristic symbolic execution applied rule choose right

And obtained the following new goals

Rule argument

Additional information