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Proof step 7 from proof inv-init (
previous step
)
err = err0, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ∃ pebs. err = ESUCCESS → mtd-cons(pebs)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 8
:
⊦ ∃ pebs. mtd-cons(pebs)
Rule argument
Additional information