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Proof step 1 from proof reduce-mtd-cons (conclusion)

⊦ mtd-cons(pebs0) → (mtd-cons(pebs1) ↔ (∀ n. n < # pebs1 ∧ (n < # pebs0 → mtd-valid-peb(pebs0[n])) → mtd-valid-peb(pebs1[n])))

System applied rule normalize

And obtained the following new goals

Rule argument

Additional information