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Proof step 9 from proof crash-neutral-recover (previous step)

# lpt = # avol, adr = adr3, lpt2 = lpt, m = m3, ns = ns3, plog = plog0, ebm-vol-inv(avol), avol ⊆ avol0 ⊦ ⟨if EIO = ESUCCESS then adr0 := adr, m0 := m, log := plog, lpt0 := lpt, ns0 := ns else avol := ?, adr := ?, m := ?, plog := ?, lpt := ?, adr0 := ?, m0 := ?, log := ?, lpt0 := ?, ns0 := ?, ns := ?⟩ (adr3 = adr ∧ m3 = m ∧ plog0 = plog ∧ lpt2 = lpt ∧ avol ⊆ avol0 ∧ ns3 = ns)

Heuristic symbolic execution applied rule if negative right

And obtained the following new goals

Proof step 10:
# lpt = # avol, adr = adr3, lpt2 = lpt, m = m3, ns = ns3, plog = plog0, ebm-vol-inv(avol), avol ⊆ avol0 ⊦ ⟨avol := ?, adr := ?, m := ?, plog := ?, lpt := ?, adr0 := ?, m0 := ?, log := ?, lpt0 := ?, ns0 := ?, ns := ?⟩ (adr3 = adr ∧ m3 = m ∧ plog0 = plog ∧ lpt2 = lpt ∧ avol ⊆ avol0 ∧ ns3 = ns)

Rule argument

Additional information

Used simplifier rules: ⊦ ESUCCESS ≠ EIO; (s)