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Proof step 6 from proof inv-format (previous step)

⊦ ⟪choose err0 with ⌊err0⌋ ∨ err0 = ESUCCESS in err := err0; lpt0 := lpt; if err = ESUCCESS then {avol := fill(mkavolume(# lpt), unmapped); adr := adr0; m := m0; plog := []; lpt := lpt0; ns := ∅} else avol := ?, adr := ?, m := ?, plog := ?, lpt := ?, ns := ?⟫ (err = ESUCCESS → ebm-vol-inv(avol) ∧ # lpt = # avol)

Heuristic symbolic execution applied rule choose right

And obtained the following new goals

Proof step 7:
⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪err := err0; lpt0 := lpt; if err = ESUCCESS then {avol := fill(mkavolume(# lpt), unmapped); adr := adr0; m := m0; plog := []; lpt := lpt0; ns := ∅} else avol := ?, adr := ?, m := ?, plog := ?, lpt := ?, ns := ?⟫ (err = ESUCCESS → ebm-vol-inv(avol) ∧ # lpt = # avol)
Proof step 20:
⊦ ∃ err0. ⌊err0⌋ ∨ err0 = ESUCCESS

Proof step 6 from proof inv-format (previous step)

Heuristic symbolic execution applied rule choose right

And obtained the following new goals

Rule argument

Additional information