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Proof step 9 from proof inv-recover (previous step)

# lpt2 = # avol1, adr0 = adr1, avol = avol0, err = err0, lpt = lpt2, lpt0 = lpt1, m0 = m1, ns0 = ns1, ebm-vol-inv(avol1), avol1 ⊆ avol0, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪avol := ?, adr := ?, m := ?, plog := ?, lpt := ?, adr0 := ?, m0 := ?, log := ?, lpt0 := ?, ns0 := ?, ns := ?⟫ (err = ESUCCESS → ebm-vol-inv(avol) ∧ # lpt = # avol), err = ESUCCESS

Heuristic symbolic execution applied rule assign right

And closed the goal!

Rule argument

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