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Proof step 4 from proof inv-unmap (previous step)

# lpt = # avol, m = m1, m0 = m2, m2 < # avol, ebm-vol-inv(avol) ⊦ ⟪if m0 < # avol then avol[m0] := unmapped else abort⟫ (ebm-vol-inv(avol) ∧ # lpt = # avol)

Heuristic symbolic execution applied rule if positive right

And obtained the following new goals

Proof step 5:
# lpt = # avol, m = m1, m0 = m2, m2 < # avol, ebm-vol-inv(avol) ⊦ ⟪avol[m0] := unmapped⟫ (ebm-vol-inv(avol) ∧ # lpt = # avol)

Rule argument

pos: right 1

Additional information

Used simplifier rules: ⊦ m < n ↔ ¬ n ≤ m; (ss)% ⊦ m < n → (n ≤ m ↔ false); (s)