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Proof step 15 from proof is-encoded-app-one (previous step)

# buf3 = EB_PAGE_SIZE, # buf0 = EB_PAGE_SIZE, # buf = EB_PAGE_SIZE, buf2 + buf0 = buf1 + buf, is-encoded(nx0, buf1), is-encoded(rnode(n), buf), is-encoded(nx0 + n ', buf1 + buf), is-encoded(rnode(n), buf0), is-encoded(nx0, buf2), is-encoded(rnode(m), buf3) ⊦ ∃ buf, buf4. (buf3 + buf2) + buf0 = buf + buf4 ∧ is-encoded(rnode(m), buf) ∧ is-encoded(nx0 + n ', buf4)

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 1 terms: buf3, buf1 + buf

Additional information

Used simplifier rules: ⊦ buf + buf0 = buf + buf1 ↔ buf0 = buf1; (s)%append-a: ⊦ (buf + buf0) + buf1 = buf + buf0 + buf1; from specification array-splice[buffer]% ⊦ is-encoded(rnd, buf) → (is-encoded(rnd0, buf) ↔ rnd = rnd0); (s) Used terms: buf3, buf1 + buf