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Proof step 5 from proof is-encoded-app-one (previous step)

# buf1 = EB_PAGE_SIZE, is-encoded(rnode(m), buf1), is-encoded(nx0 + n ', buf0), ∀ n, buf. is-encoded(nx0 + n ', buf) ↔ (∃ buf0, buf1. buf = buf0 + buf1 ∧ is-encoded(nx0, buf0) ∧ is-encoded(rnode(n), buf1)) ⊦ ∃ buf3, buf2. buf1 + buf0 = buf3 + buf2 ∧ (∃ buf2, buf1. buf3 = buf2 + buf1 ∧ is-encoded(rnode(m), buf2) ∧ is-encoded(nx0, buf1)) ∧ is-encoded(rnode(n), buf2)

User applied rule all left

And obtained the following new goals

Proof step 6:
# buf1 = EB_PAGE_SIZE, is-encoded(nx0 + n ', buf0) ↔ (∃ buf2, buf1. buf0 = buf2 + buf1 ∧ is-encoded(nx0, buf2) ∧ is-encoded(rnode(n), buf1)), is-encoded(nx0 + n ', buf0), is-encoded(rnode(m), buf1) ⊦ ∃ buf3, buf2. buf1 + buf0 = buf3 + buf2 ∧ (∃ buf2, buf1. buf3 = buf2 + buf1 ∧ is-encoded(rnode(m), buf2) ∧ is-encoded(nx0, buf1)) ∧ is-encoded(rnode(n), buf2)

Rule argument

pos: left 4 terms: n, buf0 abort: F discard: T computed: T

Additional information

Used terms: n, buf0