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Proof step 9 from proof is-encoded-app-one (previous step)

# buf2 = EB_PAGE_SIZE, # buf1 = EB_PAGE_SIZE, is-encoded(rnode(n), buf2), is-encoded(nx0, buf), is-encoded(nx0 + n ', buf + buf2), is-encoded(rnode(m), buf1) ⊦ ∃ buf2, buf0. buf1 + buf = buf2 + buf0 ∧ is-encoded(rnode(m), buf2) ∧ is-encoded(nx0, buf0)

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 1 terms: buf1, buf

Additional information

Used simplifier rules: ⊦ is-encoded(rnd, buf) → (is-encoded(rnd0, buf) ↔ rnd = rnd0); (s) Used terms: buf1, buf