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Proof step 11 from proof is-encoded-app (previous step)

# buf3 = EB_PAGE_SIZE, is-encoded(rnode(m), buf3), is-encoded(nx, buf2), is-encoded(nx1, buf0), ∀ nx1, buf. is-encoded(nx + nx1, buf) ↔ (∃ buf0, buf1. buf = buf0 + buf1 ∧ is-encoded(nx, buf0) ∧ is-encoded(nx1, buf1)) ⊦ ∃ buf, buf4. (buf3 + buf2) + buf0 = buf + buf4 ∧ is-encoded(rnode(m), buf) ∧ is-encoded(nx + nx1, buf4)

User applied rule exists right

And obtained the following new goals

Proof step 12:
# buf3 = EB_PAGE_SIZE, is-encoded(nx1, buf0), is-encoded(nx, buf2), is-encoded(rnode(m), buf3), ∀ nx1, buf. is-encoded(nx + nx1, buf) ↔ (∃ buf0, buf1. buf = buf0 + buf1 ∧ is-encoded(nx, buf0) ∧ is-encoded(nx1, buf1)) ⊦ (buf3 + buf2) + buf0 = buf3 + buf2 + buf0 ∧ is-encoded(rnode(m), buf3) ∧ is-encoded(nx + nx1, buf2 + buf0)

Rule argument

pos: right 1 terms: buf3, buf2 + buf0 abort: F discard: T computed: F

Additional information

Used terms: buf3, buf2 + buf0