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Proof step 4 from proof is-encoded-emptypage-middle (previous step)

is-aligned(# buf, EB_PAGE_SIZE), is-encoded([], buf + emptypage + buf1) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
emptypage = mkbuf(0) ⊦

Rule argument

Additional information

Used simplifier rules: is-encoded-base: ⊦ is-encoded([], buf) ↔ buf = mkbuf(0);%n ≠ 0 ⊦ is-aligned(n, n); (s)% ⊦ EB_PAGE_SIZE ≠ 0; (s)% ⊦ # emptypage = EB_PAGE_SIZE; (s)%append-a: ⊦ (buf + buf0) + buf1 = buf + buf0 + buf1; from specification array-splice[buffer]% ⊦ buf + buf0 = mkbuf(0) ↔ buf = mkbuf(0) ∧ buf0 = mkbuf(0); (ws)