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Proof step 3 from proof is-encoded-one (
previous step
)
⊦ is-encoded(m + [], buf) ↔ is-encoded(rnode(m), buf)
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 4
:
⊦ n + nx = n ' + nx
Proof step 5
:
⊦ is-encoded(m ' + [], buf) ↔ is-encoded(rnode(m), buf)
Rule argument
spec: list, inst: nat-list-set name: c seq: ⊦ n + nx = n ' + nx subst: [nx, n] → [[], m] flags: <all paths>
Additional information
Used terms: [], m