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Proof step 10 from proof is-encoded-unique (previous step)

# buf = EB_PAGE_SIZE, is-encoded(nx, buf2), is-encoded(nx1, buf2), is-encoded(rnode(m0), buf), ∀ nx0, buf. is-encoded(nx0, buf) ∧ is-encoded(nx, buf) → nx0 = nx ⊦ nx1 = nx

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 5 terms: nx1, buf2

Additional information

Used terms: nx1, buf2