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Proof step 2 from proof encoding-unique-h (previous step)

# lpt0 = # lpt1, is-encoded(lpt0, buf, n), n ≤ # lpt0 ⊦ is-encoded(lpt1, buf, n) ↔ subarray(lpt0, 0, n) = subarray(lpt1, 0, n)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information