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Proof step 20 from proof encoding-unique-h (previous step)

# buf = align↑(# lpt1 * ENCODED_LPROPS_SIZE, LEB_SIZE), # lpt0 = # lpt1, m < # lpt1, m < n, is-encoded(lpt0[m], subarray(buf, m * ENCODED_LPROPS_SIZE, ENCODED_LPROPS_SIZE)), n ≤ # lpt1, ∀ n0. n0 < n → lpt0[n0] = lpt1[n0] ⊦ lpt0[m] = lpt1[m]

User applied rule all left

And closed the goal!

Rule argument

pos: left 7 terms: m abort: F discard: T computed: T

Additional information

Used terms: m