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Proof step 1 from proof is-encoded-split-one (conclusion)

⊦ is-encoded(ns, buf0) ∧ is-encoded(n, buf1) ∧ ¬ n ∈ ns → (is-encoded(ns1, buf0 + buf1) ↔ ns1 = ns ++ n)

System applied rule normalize

And obtained the following new goals

Rule argument

Additional information