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Proof step 1 from proof avol-down-size (conclusion)

⊦ m = # avol0 ∧ avol0 ⊆ avol1 → (n = # avol1 ↔ n = m)

System applied rule normalize

And obtained the following new goals

Proof step 2:
m = # avol0, avol0 ⊆ avol1 ⊦ n = # avol1 ↔ n = m

Rule argument

Additional information