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Proof step 1 from proof id-circle-subarray-concrete-below (conclusion)

n0 < n, n + m + m0 ≤ # avol ⊦ id○(avol, avol0, (* n0)) → subarray(avol, (* n) + m, m0) = subarray(avol0, n + m, m0)

System applied rule normalize

And obtained the following new goals

Rule argument

Additional information