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Proof step 24 from proof inv-read (previous step)

m6 + # lpt = # avol, avol[m6 + m8] = mapped(buf4), avol[m2] = mapped(buf3), avol[m3] = mapped(buf2), avol[0] = mapped(buf1), m8 < # lpt, disk-layout(mksb(adr, m1, m2, m3, m4, m5, m6), # lpt), ebm-vol-inv(avol), is-encoded(mksb(adr, m1, m2, m3, m4, m5, m6), buf1), is-encoded(lpt, lebs(avol, m5, lptlebs(# lpt, LEB_SIZE))), is-encoded(log, buf3), is-encoded-pad(orphans, m4, buf2), mapped-full?(avol, m5, lptlebs(# lpt, LEB_SIZE)), m7 + n1 ≤ LEB_SIZE, n2 + n1 ≤ # buf, logoff ≠ LEB_SIZE → # buf3 = logoff, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ err0 = ESUCCESS, ∀ buf1. # buf1 = # buf → range=(buf, 0, buf1, 0, n2) → # buf ≥ n2 + n1

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ m ≤ n → (n < m ↔ false); (s)% ⊦ m ≤ n ↔ ¬ n < m; (ss)% ⊦ n ≥ m ↔ m ≤ n; (s)