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Proof step 25 from proof prepost-decode-lpt (previous step)

# lpt2 = n1 + n0, # lpt1 = n1 + n0, # buf = lptsize(n1 + n0, LEB_SIZE), m < n1 + n0, is-encoded(lpt1, buf, n0), is-encoded(lp0, subarray(buf, n0 * ENCODED_LPROPS_SIZE, ENCODED_LPROPS_SIZE)), n0 * ENCODED_LPROPS_SIZE + ENCODED_LPROPS_SIZE ≤ # buf, m ≤ n0 ⊦ m = n0, n1 = 0, is-encoded(lpt1[n0, lp0][m], subarray(buf, m * ENCODED_LPROPS_SIZE, ENCODED_LPROPS_SIZE))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 26:
# lpt2 = n1 + n0, # lpt1 = n1 + n0, # buf = lptsize(n1 + n0, LEB_SIZE), m < n0, m < n1 + n0, is-encoded(lpt1, buf, n0), is-encoded(lp0, subarray(buf, n0 * ENCODED_LPROPS_SIZE, ENCODED_LPROPS_SIZE)), n0 * ENCODED_LPROPS_SIZE + ENCODED_LPROPS_SIZE ≤ # buf ⊦ m = n0, n1 = 0, is-encoded(lpt1[m], subarray(buf, m * ENCODED_LPROPS_SIZE, ENCODED_LPROPS_SIZE))

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ n < m → lpt[m, lp][n] = lpt[n]; (s)% ⊦ m ≠ n → (m ≤ n ↔ m < n); (s)