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Proof step 1 from proof rangeeq-subarray (conclusion)

⊦ range=(avol, 5 + n, avol0, 5 + n, n + m0) → subarray(avol, 5 + 2 * n, m0) = subarray(avol0, 5 + 2 * n, m0)

System applied rule normalize

And obtained the following new goals

Proof step 2:
range=(avol, 5 + n, avol0, 5 + n, n + m0) ⊦ subarray(avol, 5 + 2 * n, m0) = subarray(avol0, 5 + 2 * n, m0)

Rule argument

Additional information