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Proof step 2 from proof disk-layout-log-above-main (previous step)

disk-layout(mksb(adr, n0, n1, n2, m, n3, n), mainareasize), n ≤ n1 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
5 + 2 * lptlebs(mainareasize, LEB_SIZE) ≤ n1, n1 = 1 ∧ n2 = 3 ∧ n3 = 5 ∨ n1 = 2 ∧ n2 = 4 ∧ n3 = 5 + lptlebs(mainareasize, LEB_SIZE) ⊦

Rule argument

Additional information

Used simplifier rules: disk-layout: ⊦ disk-layout(sb, mainareasize) ↔ ( sb.log = SB_LOG ∧ sb.orph = SB_ORPH ∧ sb.lpt = SB_LPT ∨ sb.log = SB_LOG + 1 ∧ sb.orph = SB_ORPH + 1 ∧ sb.lpt = SB_LPT + lptlebs(mainareasize, LEB_SIZE)) ∧ sb.main = SB_LPT + 2 * lptlebs(mainareasize, LEB_SIZE);%sb-log: ⊦ SB_LOG = 1;%sb-orph: ⊦ SB_ORPH = 3;%sb-lpt: ⊦ SB_LPT = 5;% ⊦ mksb(adr, m, m0, m1, m2, m3, m4).main = m4; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ mksb(adr, m, m0, m1, m2, m3, m4).lpt = m3; (s)% ⊦ mksb(adr, m, m0, m1, m2, m3, m4).orph = m1; (s)% ⊦ mksb(adr, m, m0, m1, m2, m3, m4).log = m0; (s)