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Proof step 3 from proof lebs-crash (previous step)

n + m ≤ # avol0, avol0 ⊆ avol1, ∀ n0. n ≤ n0 ∧ n0 < n + m ∧ n0 < # avol0 → avol0[n0].mapped? ∧ # avol0[n0].data = LEB_SIZE ⊦ lebs(avol1, n, m) = lebs(avol0, n, m)

User applied rule structural induction

And obtained the following new goals

Proof step 4:
n + m0 +1 ≤ # avol0, avol0 ⊆ avol1, ∀ n0. n ≤ n0 ∧ n0 < n + m0 +1 ∧ n0 < # avol0 → avol0[n0].mapped? ∧ # avol0[n0].data = LEB_SIZE, ∀ n, avol0, avol1. n + m0 ≤ # avol0 ∧ avol0 ⊆ avol1 ∧ (∀ n0. n ≤ n0 ∧ n0 < n + m0 ∧ n0 < # avol0 → avol0[n0].mapped? ∧ # avol0[n0].data = LEB_SIZE) → lebs(avol1, n, m0) = lebs(avol0, n, m0) ⊦ lebs(avol1, n, m0 +1) = lebs(avol0, n, m0 +1)

Rule argument

indvar: m

Additional information

Used simplifier rules: lebs-base: ⊦ lebs(avol, n, 0) = mkbuf(0);%nat freely generated by 0, +1;;