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Proof step 3 from proof lebs-write-above (previous step)

n + m ≤ n0, n + m ≤ # avol ⊦ lebs(avol[n0, aleb], n, m) = lebs(avol, n, m)

User applied rule structural induction

And obtained the following new goals

Proof step 4:
n + m0 +1 ≤ # avol, n + m0 +1 ≤ n0, ∀ n, n0, avol, aleb. n + m0 ≤ n0 ∧ n + m0 ≤ # avol → lebs(avol[n0, aleb], n, m0) = lebs(avol, n, m0) ⊦ lebs(avol[n0, aleb], n, m0 +1) = lebs(avol, n, m0 +1)

Rule argument

indvar: m

Additional information

Used simplifier rules: lebs-base: ⊦ lebs(avol, n, 0) = mkbuf(0);%nat freely generated by 0, +1;;