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Proof step 2 from proof lebs-write-below (previous step)

n0 < n, n + m ≤ # avol ⊦ lebs(avol[n0, aleb], n, m) = lebs(avol, n, m)

User applied rule structural induction

And obtained the following new goals

Proof step 3:
n0 < n, n + m0 +1 ≤ # avol, ∀ n0, n, avol, aleb. n0 < n ∧ n + m0 ≤ # avol → lebs(avol[n0, aleb], n, m0) = lebs(avol, n, m0) ⊦ lebs(avol[n0, aleb], n, m0 +1) = lebs(avol, n, m0 +1)

Rule argument

indvar: m

Additional information

Used simplifier rules: lebs-base: ⊦ lebs(avol, n, 0) = mkbuf(0);%nat freely generated by 0, +1;;