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Proof step 1 from proof mapped-full-aligndown-vol (conclusion)

⊦ avol0 ⊆ avol1 ∧ mapped-full?(avol0, n, m) → mapped-full?(avol1, n, m)

System applied rule normalize

And obtained the following new goals

Proof step 2:
mapped-full?(avol0, n, m), avol0 ⊆ avol1 ⊦ mapped-full?(avol1, n, m)

Rule argument

Additional information