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Proof step 60 from proof refine-write (previous step)

# avol0 = # lpt + m6, avol0[0] = mapped(buf1), avol0[m3] = mapped(buf2), avol0[m2] = mapped(buf3), avol0[m6 + m8] = mapped(buf0), avol = subarray(avol0, m6, # lpt), err = ESUCCESS, m8 < # lpt, disk-layout(mksb(adr, m9, m2, m3, m4, m5, m6), # lpt), ebm-vol-inv(subarray(avol0, m6, # lpt)), ebm-vol-inv(avol0), is-aligned(m7, EB_PAGE_SIZE), is-encoded(mksb(adr, m9, m2, m3, m4, m5, m6), buf1), is-encoded(lpt, lebs(avol0, m5, lptlebs(# lpt, LEB_SIZE))), is-encoded(log, buf3), is-encoded-pad(orphans, m4, buf2), mapped-full?(avol0, m5, lptlebs(# lpt, LEB_SIZE)), m6 + # lpt ≤ # avol0, m7 ≤ LEB_SIZE, n2 ≤ # buf, # buf0 ≤ LEB_SIZE, # buf0 ≤ m7, logoff ≠ LEB_SIZE → # buf3 = logoff ⊦ ⟨skip⟩ (avol = subarray(avol0, m6, # lpt) ∧ is-encoded(log, avol0[m2].data) ∧ is-encoded-pad(orphans, m4, avol0[m3].data) ∧ ESUCCESS = err)

Heuristic symbolic execution applied rule skip right

And closed the goal!

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic% ⊦ m ≤ m; (s)% ⊦ mapped(buf).data = buf; (s)% ⊦ is-encoded(nx0, buf) → (is-encoded(nx1, buf) ↔ nx0 = nx1); (s)%⊦ is-encoded-pad(ns0, n, buf) → (is-encoded-pad(ns1, n, buf) ↔ ns0 = ns1); (s)