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Proof step 4 from proof insert-inter-notin-dom-nodes (
previous step
)
⊦ adr ∈ st, ∀ adr0. adr0 ∈ (as ++ adr) ∩ dom nodes(st) ↔ adr0 ∈ as ∩ dom nodes(st)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 5
:
⊦ adr0 ∈ (as ++ adr) ∩ dom nodes(st) ↔ adr0 ∈ as ∩ dom nodes(st), adr ∈ st
Rule argument
Additional information