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Proof step 15 from proof nodes-alloc-append (previous step)

adr = @(m2, m3, m4) ⊦ adr = @(n, m, m0), n ∈ st, (m2 ∈ st[n, mkblock(a ', @(m, m0) ', m1)] ∧ @(m3, m4) ∈ st[n, mkblock(a ', @(m, m0) ', m1)][m2].ladrlist → adr ∈ st) ∧ ( m2 ∈ st[n, mkblock(a ', @(m, m0) ', m1)] ∧ @(m3, m4) ∈ st[n, mkblock(a ', @(m, m0) ', m1)][m2].ladrlist → st[n, mkblock(a ', @(m, m0) ', m1)][adr] = nodes(st)[adr])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
⊦ @(m2, m3, m4) = @(n, m, m0), n ∈ st, (m2 ∈ st[n, mkblock(a ', @(m, m0) ', m1)] ∧ @(m3, m4) ∈ st[n, mkblock(a ', @(m, m0) ', m1)][m2].ladrlist → @(m2, m3, m4) ∈ st) ∧ ( m2 ∈ st[n, mkblock(a ', @(m, m0) ', m1)] ∧ @(m3, m4) ∈ st[n, mkblock(a ', @(m, m0) ', m1)][m2].ladrlist → st[n, mkblock(a ', @(m, m0) ', m1)][@(m2, m3, m4)] = nodes(st)[@(m2, m3, m4)])

Proof step 15 from proof nodes-alloc-append (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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