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Proof step 8 from proof nodes-alloc (previous step)

adr = @(m0, m1, m2) ⊦ n ∈ st, (m0 ∈ st[n, mkblock([], [], m)] ∧ @(m1, m2) ∈ st[n, mkblock([], [], m)][m0].ladrlist → adr ∈ st) ∧ (m0 ∈ st[n, mkblock([], [], m)] ∧ @(m1, m2) ∈ st[n, mkblock([], [], m)][m0].ladrlist → st[n, mkblock([], [], m)][adr] = nodes(st)[adr])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
⊦ n ∈ st, (m0 ∈ st[n, mkblock([], [], m)] ∧ @(m1, m2) ∈ st[n, mkblock([], [], m)][m0].ladrlist → @(m0, m1, m2) ∈ st) ∧ ( m0 ∈ st[n, mkblock([], [], m)] ∧ @(m1, m2) ∈ st[n, mkblock([], [], m)][m0].ladrlist → st[n, mkblock([], [], m)][@(m0, m1, m2)] = nodes(st)[@(m0, m1, m2)])

Proof step 8 from proof nodes-alloc (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information